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what is the energy of one of these photons

Photon energy is the energy carried past a single photon. The sum of energy is flat proportional to the photon's electromagnetic frequency and thusly, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.

Photon energy can be expressed using any building block of energy. Among the units commonly used to denote photon energy are the electronvolt (electron volt) and the joule (as well as its multiples, such as the microjoule). As one watt second equals 6.24 × 1018 eV, the larger units may be more useful in denoting the energy of photons with higher frequency and higher energy, so much as gamma rays, arsenic opposed to lower energy photons, such as those in the radio frequency region of the electromagnetic spectrum.

Formulas [edit]

Physics [edit]

Photon energy is directly proportional to frequency.[1]

E = h f {\displaystyle E=hf}

where

This par is better-known as the Planck-Einstein relation.

To boot,

E = h c λ {\displaystyle E={\frac {hc}{\lambda }}}

where

  • E is photon muscularity (Joules),
  • λ is the photon's wavelength (metres),
  • c is the light speed in vacuum - 299792458 metres per second
  • h is the Planck constant - 6.62607015 × 10−34 (m2kgs−1)

The photon energy at 1 Cps is equal to 6.62607015 × 10−34 J

That is adequate to 4.135667697 × 10−15 electron volt (electronvolts)

Electronvolts [edit]

Energy Department is often sounded in electronvolts.

To find the photon energy in electronvolts victimisation the wavelength in micrometres, the par is approximately

E  (eV) = 1.2398 λ  (μm) {\displaystyle E{\text{ (eV)}}={\frac {1.2398}{\lambda {\text{ (μm)}}}}}

This equating only holds if the wavelength is unhurried in micrometers.

The photon energy at 1 μm wavelength, the wavelength of neighbouring infrared emission, is approximately 1.2398 eV.

In chemistry, quantum physics and optical engineering [edit]

See [2]

E = h ν {\displaystyle E=h{\nu }}

where

  • E is photon get-up-and-go (joules),
  • h is the Max Planck constant - 6.62607015 × 10−34 (m2kgs−1)
  • The Greek letter ν (nu) is the photon's frequency.

Examples [edit]

An FM radio send transmitting at 100 M emits photons with an energy of about 4.1357 × 10−7 eV. This minuscule amount of energy is approximately 8 × 10−13 times the electron's good deal (via mass-energy equality).

Precise-high-energy gamma rays have photon energies of 100 GeV to over 1 PeV (1011 to 1015 electronvolts) or 16 nanojoules to 160 microjoules.[3] This corresponds to frequencies of 2.42 × 1025 to 2.42 × 1029 Hz.

During photosynthesis, specific chlorophyll molecules absorb red-light photons at a wavelength of 700 micromillimeter in the photosystem I, corresponding to an energy of each photon of ≈ 2 eV ≈ 3 x 10−19 J ≈ 75 kBT, where kBT denotes the spring energy. A minimum of 48 photons is needed for the synthesis of a lonesome glucose molecule from CO2 and water (chemical potential difference 5 x 10−18 J) with a supreme energy conversion efficiency of 35%

Fancy besides [edit]

  • Photon
  • Nonparticulate radiation
  • Magnetic force spectrum
  • Planck constant and Planck units
  • Planck–Einstein relation
  • Soft photon

References [edit]

  1. ^ "Energy of Photon". Photovoltaic Training Network, pveducation.org. Archived from the original along 2016-07-12. Retrieved 2015-06-21 .
  2. ^ Andrew Liddle (27 April 2015). An Introduction to Modern Cosmology. John the Divin Wiley & Sons. p. 16. ISBN978-1-118-69025-3.
  3. ^ Sciences, Taiwanese Academy of. "Lookout station discovers a dozen PeVatrons and photons exceeding 1 PeV, launches ultra-high-energy gamma astronomy epoch". phys.org . Retrieved 2021-11-25 .

what is the energy of one of these photons

Source: https://en.wikipedia.org/wiki/Photon_energy

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